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7x^2+12x-19=0
a = 7; b = 12; c = -19;
Δ = b2-4ac
Δ = 122-4·7·(-19)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-26}{2*7}=\frac{-38}{14} =-2+5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+26}{2*7}=\frac{14}{14} =1 $
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