7x2+24x=-20

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Solution for 7x2+24x=-20 equation:



7x^2+24x=-20
We move all terms to the left:
7x^2+24x-(-20)=0
We add all the numbers together, and all the variables
7x^2+24x+20=0
a = 7; b = 24; c = +20;
Δ = b2-4ac
Δ = 242-4·7·20
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4}{2*7}=\frac{-28}{14} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4}{2*7}=\frac{-20}{14} =-1+3/7 $

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