7x2+32x=15

Solution for 7x2+32x=15 equation:

7x^2+32x=15

We move all terms to the left:

7x^2+32x-(15)=0

a = 7; b = 32; c = -15;
Δ = b2-4ac
Δ = 322-4·7·(-15)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-38}{2*7}=\frac{-70}{14}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+38}{2*7}=\frac{6}{14}
=3/7
$