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7x^2+35x+28=0
a = 7; b = 35; c = +28;
Δ = b2-4ac
Δ = 352-4·7·28
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-21}{2*7}=\frac{-56}{14} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+21}{2*7}=\frac{-14}{14} =-1 $
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