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7x^2+35x-168=0
a = 7; b = 35; c = -168;
Δ = b2-4ac
Δ = 352-4·7·(-168)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-77}{2*7}=\frac{-112}{14} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+77}{2*7}=\frac{42}{14} =3 $
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