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7x^2+36x+5=0
a = 7; b = 36; c = +5;
Δ = b2-4ac
Δ = 362-4·7·5
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-34}{2*7}=\frac{-70}{14} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+34}{2*7}=\frac{-2}{14} =-1/7 $
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