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7x^2+3x+4+7x^2+3x+4=
We move all terms to the left:
7x^2+3x+4+7x^2+3x+4-()=0
We add all the numbers together, and all the variables
14x^2+6x=0
a = 14; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·14·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*14}=\frac{-12}{28} =-3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*14}=\frac{0}{28} =0 $
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