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7x^2+3x-364=0
a = 7; b = 3; c = -364;
Δ = b2-4ac
Δ = 32-4·7·(-364)
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10201}=101$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-101}{2*7}=\frac{-104}{14} =-7+3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+101}{2*7}=\frac{98}{14} =7 $
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