7x2+42x-112=0

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Solution for 7x2+42x-112=0 equation:



7x^2+42x-112=0
a = 7; b = 42; c = -112;
Δ = b2-4ac
Δ = 422-4·7·(-112)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-70}{2*7}=\frac{-112}{14} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+70}{2*7}=\frac{28}{14} =2 $

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