7x2+49x+5x+35=0

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Solution for 7x2+49x+5x+35=0 equation:



7x^2+49x+5x+35=0
We add all the numbers together, and all the variables
7x^2+54x+35=0
a = 7; b = 54; c = +35;
Δ = b2-4ac
Δ = 542-4·7·35
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-44}{2*7}=\frac{-98}{14} =-7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+44}{2*7}=\frac{-10}{14} =-5/7 $

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