7x2+4x=1

Solution for 7x2+4x=1 equation:

7x^2+4x=1

We move all terms to the left:

7x^2+4x-(1)=0

a = 7; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·7·(-1)
Δ = 44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{44}=\sqrt{4*11}=\sqrt{4}*\sqrt{11}=2\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{11}}{2*7}=\frac{-4-2\sqrt{11}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{11}}{2*7}=\frac{-4+2\sqrt{11}}{14}
$