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7x^2+52x+60=0
a = 7; b = 52; c = +60;
Δ = b2-4ac
Δ = 522-4·7·60
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-32}{2*7}=\frac{-84}{14} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+32}{2*7}=\frac{-20}{14} =-1+3/7 $
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