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7x^2+5x=378
We move all terms to the left:
7x^2+5x-(378)=0
a = 7; b = 5; c = -378;
Δ = b2-4ac
Δ = 52-4·7·(-378)
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10609}=103$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-103}{2*7}=\frac{-108}{14} =-7+5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+103}{2*7}=\frac{98}{14} =7 $
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