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7x^2+6x+8=2x^2-8x
We move all terms to the left:
7x^2+6x+8-(2x^2-8x)=0
We get rid of parentheses
7x^2-2x^2+6x+8x+8=0
We add all the numbers together, and all the variables
5x^2+14x+8=0
a = 5; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·5·8
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6}{2*5}=\frac{-20}{10} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6}{2*5}=\frac{-8}{10} =-4/5 $
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