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7x^2+7=119
We move all terms to the left:
7x^2+7-(119)=0
We add all the numbers together, and all the variables
7x^2-112=0
a = 7; b = 0; c = -112;
Δ = b2-4ac
Δ = 02-4·7·(-112)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*7}=\frac{-56}{14} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*7}=\frac{56}{14} =4 $
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