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7x^2+8x=12
We move all terms to the left:
7x^2+8x-(12)=0
a = 7; b = 8; c = -12;
Δ = b2-4ac
Δ = 82-4·7·(-12)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-20}{2*7}=\frac{-28}{14} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+20}{2*7}=\frac{12}{14} =6/7 $
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