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7x^2-13x-1=0
a = 7; b = -13; c = -1;
Δ = b2-4ac
Δ = -132-4·7·(-1)
Δ = 197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{197}}{2*7}=\frac{13-\sqrt{197}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{197}}{2*7}=\frac{13+\sqrt{197}}{14} $
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