If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7x^2-15=45
We move all terms to the left:
7x^2-15-(45)=0
We add all the numbers together, and all the variables
7x^2-60=0
a = 7; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·7·(-60)
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{105}}{2*7}=\frac{0-4\sqrt{105}}{14} =-\frac{4\sqrt{105}}{14} =-\frac{2\sqrt{105}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{105}}{2*7}=\frac{0+4\sqrt{105}}{14} =\frac{4\sqrt{105}}{14} =\frac{2\sqrt{105}}{7} $
| 6(x+11/4)=10 | | g=5.73=8 | | g+569=845 | | -6x=4x+6 | | 5m-13=47=m=11 | | 6(1/2x-1/3)=(2x-1/2) | | 2+–9d=–70 | | 37=4x | | 2a-4(a-5)=10= | | –4−9c=–10c | | 4=u+31/10 | | -4(t+5)=20 | | I05=5n | | 9b+3=48 | | I÷3-8=13t= | | 1.7+c=4.7 | | 85=5(k+9) | | (3x-2)=4816 | | 40=m/18 | | 20=−4x−6x | | -10=0−n3−10=0 | | x^2+27x-79=0 | | 3+x=1+x•x | | 0.25(4m-12)=12+4m-9 | | 2(x-3)=-(6x-4) | | (b)/(9)+(1)/(8)=19 | | x−15=−5 | | 45=5(b−88) | | 6+7x-3=x+2x+3 | | (2x+3))(x+2)=0 | | v+15=53 | | x/12+5=-7 |