7x2-17x+6=0

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Solution for 7x2-17x+6=0 equation:



7x^2-17x+6=0
a = 7; b = -17; c = +6;
Δ = b2-4ac
Δ = -172-4·7·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-11}{2*7}=\frac{6}{14} =3/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+11}{2*7}=\frac{28}{14} =2 $

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