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7x^2-23x+6=0
a = 7; b = -23; c = +6;
Δ = b2-4ac
Δ = -232-4·7·6
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-19}{2*7}=\frac{4}{14} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+19}{2*7}=\frac{42}{14} =3 $
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