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7x^2-26x-8=0
a = 7; b = -26; c = -8;
Δ = b2-4ac
Δ = -262-4·7·(-8)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-30}{2*7}=\frac{-4}{14} =-2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+30}{2*7}=\frac{56}{14} =4 $
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