7x2-27x+28=4x2-15x+16

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Solution for 7x2-27x+28=4x2-15x+16 equation: 



7x^2-27x+28=4x^2-15x+16

We move all terms to the left:

7x^2-27x+28-(4x^2-15x+16)=0

We get rid of parentheses

7x^2-4x^2-27x+15x-16+28=0

We add all the numbers together, and all the variables

3x^2-12x+12=0

a = 3; b = -12; c = +12;
Δ = b2-4ac
Δ = -122-4·3·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{6}=2$

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