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7x^2-30x+27=0
a = 7; b = -30; c = +27;
Δ = b2-4ac
Δ = -302-4·7·27
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-12}{2*7}=\frac{18}{14} =1+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+12}{2*7}=\frac{42}{14} =3 $
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