7x2-3x-2=0

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Solution for 7x2-3x-2=0 equation: 



7x^2-3x-2=0

a = 7; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·7·(-2)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{65}}{2*7}=\frac{3-\sqrt{65}}{14}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{65}}{2*7}=\frac{3+\sqrt{65}}{14}
$

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