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7x^2-567=0
a = 7; b = 0; c = -567;
Δ = b2-4ac
Δ = 02-4·7·(-567)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*7}=\frac{-126}{14} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*7}=\frac{126}{14} =9 $
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