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7x^2-8x=3x+20
We move all terms to the left:
7x^2-8x-(3x+20)=0
We get rid of parentheses
7x^2-8x-3x-20=0
We add all the numbers together, and all the variables
7x^2-11x-20=0
a = 7; b = -11; c = -20;
Δ = b2-4ac
Δ = -112-4·7·(-20)
Δ = 681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{681}}{2*7}=\frac{11-\sqrt{681}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{681}}{2*7}=\frac{11+\sqrt{681}}{14} $
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