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7x^2-98x+336=0
a = 7; b = -98; c = +336;
Δ = b2-4ac
Δ = -982-4·7·336
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-14}{2*7}=\frac{84}{14} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+14}{2*7}=\frac{112}{14} =8 $
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