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7x^2/25=6
We move all terms to the left:
7x^2/25-(6)=0
We multiply all the terms by the denominator
7x^2-6*25=0
We add all the numbers together, and all the variables
7x^2-150=0
a = 7; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·7·(-150)
Δ = 4200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4200}=\sqrt{100*42}=\sqrt{100}*\sqrt{42}=10\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{42}}{2*7}=\frac{0-10\sqrt{42}}{14} =-\frac{10\sqrt{42}}{14} =-\frac{5\sqrt{42}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{42}}{2*7}=\frac{0+10\sqrt{42}}{14} =\frac{10\sqrt{42}}{14} =\frac{5\sqrt{42}}{7} $
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