7x2/5x=1

Solution for 7x2/5x=1 equation:

7x^2/5x=1

We move all terms to the left:

7x^2/5x-(1)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We multiply all the terms by the denominator


7x^2-1*5x=0

Wy multiply elements

7x^2-5x=0

a = 7; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·7·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*7}=\frac{0}{14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*7}=\frac{10}{14}
=5/7
$