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7x^2=2401
We move all terms to the left:
7x^2-(2401)=0
a = 7; b = 0; c = -2401;
Δ = b2-4ac
Δ = 02-4·7·(-2401)
Δ = 67228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{67228}=\sqrt{9604*7}=\sqrt{9604}*\sqrt{7}=98\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-98\sqrt{7}}{2*7}=\frac{0-98\sqrt{7}}{14} =-\frac{98\sqrt{7}}{14} =-7\sqrt{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+98\sqrt{7}}{2*7}=\frac{0+98\sqrt{7}}{14} =\frac{98\sqrt{7}}{14} =7\sqrt{7} $
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