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7x^2=42
We move all terms to the left:
7x^2-(42)=0
a = 7; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·7·(-42)
Δ = 1176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1176}=\sqrt{196*6}=\sqrt{196}*\sqrt{6}=14\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{6}}{2*7}=\frac{0-14\sqrt{6}}{14} =-\frac{14\sqrt{6}}{14} =-\sqrt{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{6}}{2*7}=\frac{0+14\sqrt{6}}{14} =\frac{14\sqrt{6}}{14} =\sqrt{6} $
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