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7x^2=5x+18
We move all terms to the left:
7x^2-(5x+18)=0
We get rid of parentheses
7x^2-5x-18=0
a = 7; b = -5; c = -18;
Δ = b2-4ac
Δ = -52-4·7·(-18)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-23}{2*7}=\frac{-18}{14} =-1+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+23}{2*7}=\frac{28}{14} =2 $
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