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7x^2=72x+3
We move all terms to the left:
7x^2-(72x+3)=0
We get rid of parentheses
7x^2-72x-3=0
a = 7; b = -72; c = -3;
Δ = b2-4ac
Δ = -722-4·7·(-3)
Δ = 5268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5268}=\sqrt{4*1317}=\sqrt{4}*\sqrt{1317}=2\sqrt{1317}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-2\sqrt{1317}}{2*7}=\frac{72-2\sqrt{1317}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+2\sqrt{1317}}{2*7}=\frac{72+2\sqrt{1317}}{14} $
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