7x=(x+2)(x+4)

Solution for 7x=(x+2)(x+4) equation:

7x=(x+2)(x+4)

We move all terms to the left:

7x-((x+2)(x+4))=0

We multiply parentheses ..

-((+x^2+4x+2x+8))+7x=0


We calculate terms in parentheses: -((+x^2+4x+2x+8)), so:

(+x^2+4x+2x+8)

We get rid of parentheses

x^2+4x+2x+8

We add all the numbers together, and all the variables

x^2+6x+8

Back to the equation:

-(x^2+6x+8)


We add all the numbers together, and all the variables

7x-(x^2+6x+8)=0

We get rid of parentheses

-x^2+7x-6x-8=0

We add all the numbers together, and all the variables

-1x^2+x-8=0

a = -1; b = 1; c = -8;
Δ = b2-4ac
Δ = 12-4·(-1)·(-8)
Δ = -31
Delta is less than zero, so there is no solution for the equation