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7x=3(2x+1)-5
We move all terms to the left:
7x-(3(2x+1)-5)=0
We calculate terms in parentheses: -(3(2x+1)-5), so:We get rid of parentheses
3(2x+1)-5
We multiply parentheses
6x+3-5
We add all the numbers together, and all the variables
6x-2
Back to the equation:
-(6x-2)
7x-6x+2=0
We add all the numbers together, and all the variables
x+2=0
We move all terms containing x to the left, all other terms to the right
x=-2
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