7x=32+(64/8)-12x

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Solution for 7x=32+(64/8)-12x equation:



7x=32+(64/8)-12x
We move all terms to the left:
7x-(32+(64/8)-12x)=0
Domain of the equation: 8)-12x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
7x-(32+8-12x)=0
We get rid of parentheses
7x+12x-32-8=0
We add all the numbers together, and all the variables
19x-40=0
We move all terms containing x to the left, all other terms to the right
19x=40
x=40/19
x=2+2/19

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