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7y(4y-39)=0
We multiply parentheses
28y^2-273y=0
a = 28; b = -273; c = 0;
Δ = b2-4ac
Δ = -2732-4·28·0
Δ = 74529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{74529}=273$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-273)-273}{2*28}=\frac{0}{56} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-273)+273}{2*28}=\frac{546}{56} =9+3/4 $
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