7y(y-4)=35

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Solution for 7y(y-4)=35 equation:



7y(y-4)=35
We move all terms to the left:
7y(y-4)-(35)=0
We multiply parentheses
7y^2-28y-35=0
a = 7; b = -28; c = -35;
Δ = b2-4ac
Δ = -282-4·7·(-35)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-42}{2*7}=\frac{-14}{14} =-1 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+42}{2*7}=\frac{70}{14} =5 $

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