7y+(8=3y)=38

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Solution for 7y+(8=3y)=38 equation:



7y+(8=3y)=38
We move all terms to the left:
7y+(8-(3y))=0
We add all the numbers together, and all the variables
7y+(-3y+8)=0
We get rid of parentheses
7y-3y+8=0
We add all the numbers together, and all the variables
4y+8=0
We move all terms containing y to the left, all other terms to the right
4y=-8
y=-8/4
y=-2

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