7y+(y-5)=4(y+2)-2

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Solution for 7y+(y-5)=4(y+2)-2 equation: 



7y+(y-5)=4(y+2)-2

We move all terms to the left:

7y+(y-5)-(4(y+2)-2)=0

We get rid of parentheses

7y+y-(4(y+2)-2)-5=0



We calculate terms in parentheses: -(4(y+2)-2), so:

4(y+2)-2

We multiply parentheses

4y+8-2

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)



We add all the numbers together, and all the variables

8y-(4y+6)-5=0

We get rid of parentheses

8y-4y-6-5=0

We add all the numbers together, and all the variables

4y-11=0

We move all terms containing y to the left, all other terms to the right

4y=11

y=11/4

y=2+3/4

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