7y+1/2=-4/y-2

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Solution for 7y+1/2=-4/y-2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

7*y+1/2 = -4/y-2 // + -4/y-2

7*y-(-4/y)+1/2+2 = 0

7*y+4*y^-1+1/2+2 = 0

7*y^1+4*y^-1+5/2*y^0 = 0

(7*y^2+5/2*y^1+4*y^0)/(y^1) = 0 // * y^2

y^1*(7*y^2+5/2*y^1+4*y^0) = 0

y^1

7*y^2+(5/2)*y+4 = 0

7*y^2+(5/2)*y+4 = 0

DELTA = (5/2)^2-(4*4*7)

DELTA = -423/4

DELTA < 0

y in { } 

y belongs to the empty set

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