7y+12+-2y+42=2(-3y+38)

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Solution for 7y+12+-2y+42=2(-3y+38) equation: 



7y+12+-2y+42=2(-3y+38)

We move all terms to the left:

7y+12+-2y+42-(2(-3y+38))=0

We add all the numbers together, and all the variables

5y-(2(-3y+38))=0



We calculate terms in parentheses: -(2(-3y+38)), so:

2(-3y+38)

We multiply parentheses

-6y+76

Back to the equation:

-(-6y+76)



We get rid of parentheses

5y+6y-76=0

We add all the numbers together, and all the variables

11y-76=0

We move all terms containing y to the left, all other terms to the right

11y=76

y=76/11

y=6+10/11

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