7y+12=5X+40

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Solution for 7y+12=5X+40 equation: 



7y+12=5y+40

We move all terms to the left:

7y+12-(5y+40)=0

We get rid of parentheses

7y-5y-40+12=0

We add all the numbers together, and all the variables

2y-28=0

We move all terms containing y to the left, all other terms to the right

2y=28

y=28/2

y=14

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