7y+15-2y=7(y+3)C

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Solution for 7y+15-2y=7(y+3)C equation: 



7y+15-2y=7(y+3)

We move all terms to the left:

7y+15-2y-(7(y+3))=0

We add all the numbers together, and all the variables

5y-(7(y+3))+15=0



We calculate terms in parentheses: -(7(y+3)), so:

7(y+3)

We multiply parentheses

7y+21

Back to the equation:

-(7y+21)



We get rid of parentheses

5y-7y-21+15=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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