7y+17=3(y-1)

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Solution for 7y+17=3(y-1) equation: 



7y+17=3(y-1)

We move all terms to the left:

7y+17-(3(y-1))=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

7y-3y+3+17=0

We add all the numbers together, and all the variables

4y+20=0

We move all terms containing y to the left, all other terms to the right

4y=-20

y=-20/4

y=-5

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