7y+1=2(y+3)

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Solution for 7y+1=2(y+3) equation: 



7y+1=2(y+3)

We move all terms to the left:

7y+1-(2(y+3))=0



We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

7y-2y-6+1=0

We add all the numbers together, and all the variables

5y-5=0

We move all terms containing y to the left, all other terms to the right

5y=5

y=5/5

y=1

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