7y+2(1y-5)+1y=40

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Solution for 7y+2(1y-5)+1y=40 equation: 



7y+2(1y-5)+1y=40

We move all terms to the left:

7y+2(1y-5)+1y-(40)=0

We add all the numbers together, and all the variables

7y+2(y-5)+1y-40=0

We add all the numbers together, and all the variables

8y+2(y-5)-40=0

We multiply parentheses

8y+2y-10-40=0

We add all the numbers together, and all the variables

10y-50=0

We move all terms containing y to the left, all other terms to the right

10y=50

y=50/10

y=5

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