7y+2(3y+4)=-2(3y-2)+1

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Solution for 7y+2(3y+4)=-2(3y-2)+1 equation: 



7y+2(3y+4)=-2(3y-2)+1

We move all terms to the left:

7y+2(3y+4)-(-2(3y-2)+1)=0

We multiply parentheses

7y+6y-(-2(3y-2)+1)+8=0



We calculate terms in parentheses: -(-2(3y-2)+1), so:

-2(3y-2)+1

We multiply parentheses

-6y+4+1

We add all the numbers together, and all the variables

-6y+5

Back to the equation:

-(-6y+5)



We add all the numbers together, and all the variables

13y-(-6y+5)+8=0

We get rid of parentheses

13y+6y-5+8=0

We add all the numbers together, and all the variables

19y+3=0

We move all terms containing y to the left, all other terms to the right

19y=-3

y=-3/19

y=-3/19

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