7y+2(3y-5)=13-2(y+1)

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Solution for 7y+2(3y-5)=13-2(y+1) equation: 


Simplifying
7y + 2(3y + -5) = 13 + -2(y + 1)

Reorder the terms:
7y + 2(-5 + 3y) = 13 + -2(y + 1)
7y + (-5 * 2 + 3y * 2) = 13 + -2(y + 1)
7y + (-10 + 6y) = 13 + -2(y + 1)

Reorder the terms:
-10 + 7y + 6y = 13 + -2(y + 1)

Combine like terms: 7y + 6y = 13y
-10 + 13y = 13 + -2(y + 1)

Reorder the terms:
-10 + 13y = 13 + -2(1 + y)
-10 + 13y = 13 + (1 * -2 + y * -2)
-10 + 13y = 13 + (-2 + -2y)

Combine like terms: 13 + -2 = 11
-10 + 13y = 11 + -2y

Solving
-10 + 13y = 11 + -2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2y' to each side of the equation.
-10 + 13y + 2y = 11 + -2y + 2y

Combine like terms: 13y + 2y = 15y
-10 + 15y = 11 + -2y + 2y

Combine like terms: -2y + 2y = 0
-10 + 15y = 11 + 0
-10 + 15y = 11

Add '10' to each side of the equation.
-10 + 10 + 15y = 11 + 10

Combine like terms: -10 + 10 = 0
0 + 15y = 11 + 10
15y = 11 + 10

Combine like terms: 11 + 10 = 21
15y = 21

Divide each side by '15'.
y = 1.4

Simplifying
y = 1.4

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