7y+2(y-4)=5(y+1)-4

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Solution for 7y+2(y-4)=5(y+1)-4 equation: 



7y+2(y-4)=5(y+1)-4

We move all terms to the left:

7y+2(y-4)-(5(y+1)-4)=0

We multiply parentheses

7y+2y-(5(y+1)-4)-8=0



We calculate terms in parentheses: -(5(y+1)-4), so:

5(y+1)-4

We multiply parentheses

5y+5-4

We add all the numbers together, and all the variables

5y+1

Back to the equation:

-(5y+1)



We add all the numbers together, and all the variables

9y-(5y+1)-8=0

We get rid of parentheses

9y-5y-1-8=0

We add all the numbers together, and all the variables

4y-9=0

We move all terms containing y to the left, all other terms to the right

4y=9

y=9/4

y=2+1/4

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